#### 7, 8
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- Solving the quadratic \( t^2 - 15t + 56 = 0 \) using the quadratic formula:
- t = rac{15 \pm \sqrt{15^2 - 4 imes 56}}{2} = rac{15 \pm \sqrt{225 - 224}}{2} = rac{15 \pm 1}{2}
- The solutions are \( t = 8 \) and \( t = 7 \).
- A function \( f(x) = ax^2 + bx + c \) has a vertex at \( (2, -3) \) and passes through the point \( (1, 0) \). Find \( a \), \( b \), and \( c \).
- The vertex form is \( f(x) = a(x-2)^2 - 3 \).
- Substitute \( (1, 0) \): \( 0 = a(1-2)^2 - 3 \).
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