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/ \( 1 = A(1) \Rightarrow A = 1 \)
\( 1 = A(1) \Rightarrow A = 1 \)
February 22, 2026
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Setting \( n = -2 \):
\( 1 = B(-1) \Rightarrow B = -1 \)
Setting \( n = -1 \):
rac{1}{(n + 1)(n + 2)} = rac{1}{n + 1} - rac{1}{n + 2}
The series becomes:
\sum_{n=1}^{\infty} \left( rac{1}{n + 1} - rac{1}{n + 2}
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