11Ã17=187 â 1+8+7=16 â no
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- 11Ã14=154 â 1+5+4=10 â no
- 11Ã15=165 â 1+6+5=12 â not div by 9
- 11Ã16=176 â 1+7+6=14 â no
- 11Ã18=198 â 1+9+8=18 â divisible by 9 â yes
- So the smallest multiple of 11 in [100,199] divisible by 9 is 198.
- Therefore, the smallest possible batch size that allows full utilization (i.e., divides a valid dataset size) is $ oxed{198} $.
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