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- Parameters removed = 2,400,000 – 2,100,000 = 300,000
- Fine-tuning reintroduces 10% of removed = 0.10×300,000 = 30,000
- Final parameter count = 2,100,000 + 30,000 = 2,130,000
- A primatologist studying social bonds observes that each chimpanzee grooms exactly 3 others in a daily interaction session. In a group of 10 chimps, if each grooming pair is counted once, how many unique grooming interactions occur each day?
- This is a combination: each pair is unique. Number of ways to choose 2 chimps from 10 is C(10,2) = 10!/(2!×8!) = (10×9)/2 = 45
- But only 3 grooming partners per chimp — total directed interactions = 10×3 = 30, but since each interaction involves two chimps, unique pairs = 30 / 2 = 15
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