3(2) = 6

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• Calculate each term separately:
• 2(2)^3 = 2 \times 8 = 16
• -5(2)^2 = -5 \times 4 = -20
• Combine these results with the constant term:
• f(2) = 16 - 20 + 6 - 1 = 1
• Thus, \(f(2) = \boxed{1}\).

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