\( 6(27) = 162 > 108 \)

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• But wait — factor:
• \( 6x^3 = 108 \Rightarrow x^3 = 18 \Rightarrow x = \sqrt[3]{18} \)
• Alternatively, check if integer solution: try \( x = 3 \):
• \( x = 2 \): \( 6(8) = 48 < 108 \)
• So no integer. Answer is \( \sqrt[3]{18} \), but recheck algebra.
• But \( 18 = 27 \cdot \frac{2}{3} \), so no simplification.

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