\boxed{5\pi\sqrt{2}}

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• r = \frac{5\sqrt{2}}{2}
• C = 2\pi r = 2\pi \left(\frac{5\sqrt{2}}{2}\right) = 5\pi\sqrt{2}
• Thus, the circumference of the circle is:
• Given a triangle with sides \(7 \, \text{cm}\), \(24 \, \text{cm}\), and \(25 \, \text{cm}\), find the length of the shortest altitude.
• The triangle is a right triangle (since \(7^2 + 24^2 = 25^2\)). The area \(A\) of the triangle is:
• A = \frac{1}{2} \times 7 \times 24 = 84 \, \text{cm}^2

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