d = 4
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- d^2 + 3^2 = 5^2
- d^2 + 9 = 25
- d^2 = 16
- Thus, the shortest distance from the center to the path is $ \boxed{4} $ meters.
- Question: A robotics engineer is designing a triangular linkage mechanism where the sides measure 7 cm, 10 cm, and 13 cm. What is the radius of the inscribed circle in this triangle?
- Let the triangle have side lengths $ a = 7 $, $ b = 10 $, $ c = 13 $. First, compute the semi-perimeter $ s $:
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