medvedev president
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MARC 15 .
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1948.01.27 1948.02.19 1948.05.18 1948.06.23 1948.09.21 .
BOOK 15 BOOK.
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- 6b + 25b = 155 \Rightarrow 19b = 69 \Rightarrow b = \frac{69}{19}
This is exact. So one bead costs $ \frac{69}{19} $ gold coins. But let's double-check the original equations with integer values.
Try solving again using elimination:
Multiply first equation by 5: $ 25t + 15b = 215 $
Multiply second by 3: $ 6t + 15b = 93 $
Subtract:
Then plug into $ 5t + 3b = 43 $:
\cdot \frac{122}{19} + 3b = 43 \Rightarrow \frac{610}{19} + 3b = 43 \Rightarrow 3b = 43 - \frac{610}{19} = \frac{817 - 610}{19} = \frac{207}{19}
\Rightarrow b = \frac{69}{19}
Thus, one bead costs $ \boxed{\frac{69}{19}} $ gold coins.