To find the maximum of $ P'(t) $, we define:
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- Now compute $ D'(t) $:
- D(t) = 1 + 9e^{-0.5t} \Rightarrow D'(t) = 9 \cdot (-0.5)e^{-0.5t} = -4.5e^{-0.5t}.
- P'(t) = -1000 \cdot \frac{-4.5e^{-0.5t}}{(1 + 9e^{-0.5t})^2} = \frac{4500e^{-0.5t}}{(1 + 9e^{-0.5t})^2}.
- f(t) = \frac{e^{-0.5t}}{(1 + 9e^{-0.5t})^2}.
- Let $ u = e^{-0.5t} $, so $ f(t) = \frac{u}{(1 + 9u)^2} $. Now find the maximum of this function with respect to $ u > 0 $.
- f(u) = \frac{u}{(1 + 9u)^2}.
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